A parallel plate capacitor has plate of area A and separation d . It is charged to a potential diffe

Question

A parallel plate capacitor has plate of area A and separation d . It is charged to a potential difference $V_{0}$. The charging battery is disconnected and the plates are pulled apart to three times the initial separation. The work required to separate the plates is\

Professor PC Thomas Classes · Answer

Work = difference of PE\ $\frac{\mathrm{Q}^{2}}{2 	imes\left(\frac{\mathrm{C}}{3}ight)}-\frac{\mathrm{Q}^{2}}{2 \mathrm{C}}$\ $\mathrm{C}=\frac{\varepsilon_{0} \mathrm{~A}}{\mathrm{~d}}$ and charge $\mathrm{Q}=\mathrm{CV}_{0}$\