Two point charges are placed on $x$-axis. $2 \mu \mathrm{C}$ at $\mathrm{x}=10 \mathrm{~cm}$ and $-1

Question

Two point charges are placed on $x$-axis. $2 \mu \mathrm{C}$ at $\mathrm{x}=10 \mathrm{~cm}$ and $-1 \mu \mathrm{C}$ at $x=40 \mathrm{~cm}$. The potential at $\mathrm{x}=100 \mathrm{~cm}$ from the origin is\

Professor PC Thomas Classes · Answer

\ $\mathrm{V}=\mathrm{V}_{1}+\mathrm{V}_{2}=9 	imes 10^{9}\left[\frac{\mathrm{q}_{1}}{\mathrm{r}_{1}}+\frac{\mathrm{q}_{2}}{\mathrm{r}_{2}}ight]$\ $=9 	imes 10^{9}\left[\frac{2 	imes 10^{-6}}{0.9}+\frac{(-1) 	imes\left(10^{-6}ight)}{0.6}ight] \mathrm{V}$\