Two balls are dropped to the ground from different height. One ball is dropped 3s after the other bu

Question

Two balls are dropped to the ground from different height. One ball is dropped 3s after the other but they both strike the ground at the same time. If the first ball takes 5 s to reach the ground, then the difference initial height is $\left(\mathrm{g}=10 \mathrm{~ms}^{-2}ight)$\

Professor PC Thomas Classes · Answer

$S_{2}=\frac{1}{2} g t_{2}^{2}=\frac{10}{2} 	imes(2)^{2}=20 \mathrm{~m}$\ $\mathrm{S}_{1}=\frac{1}{2} \mathrm{gt}_{1}^{2}=\frac{10}{2} 	imes(5)^{2}=125 \mathrm{~m}$\ $	herefore \mathrm{S}_{1}-\mathrm{S}_{2}=125-20=105 \mathrm{~m}$\