In figure the approximate value of $V_{o}$ across the diode/is\ \

Question

Professor PC Thomas Classes · Answer

$V=V_{R}+V_{D}$ where\ $\mathrm{V}=$ supply voltage. This is the general\ notation. In this problem you have $\mathrm{V}_{0}$\ $\mathrm{V}_{\mathrm{R}}=$ voltage across R\ $\mathrm{V}_{\mathrm{D}}=$ voltage across diode\ $\mathrm{V}_{\mathrm{R}}=\mathrm{IR}$\ $\mathrm{V}_{\mathrm{D}}=\mathrm{I} 	imes$ resistance of diode\ In the figure the diode is reverse biased\ So $\mathrm{I}=0 \mathrm{~V}_{\mathrm{R}}=0$\ $	herefore \mathrm{V}=\mathrm{V}_{\mathrm{D}}$\ Voltage across the diode $=5 \mathrm{~V}$\