In the circuit given the current through the zener diode is\ \

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Professor PC Thomas Classes · Answer

\ The voltage drop across $\mathrm{R}_{2}$ is 10 V . Current through $1500 \Omega=\frac{10}{1500} \mathrm{~A}=6.67 \mathrm{~mA}$. Voltage drop across\ $\mathrm{R}_{1}=15 \mathrm{~V}-\mathrm{V} \mathrm{R}_{2}=15 \mathrm{~V}-10 \mathrm{~V}=5 \mathrm{~V}$\ Current through it $\frac{5}{500 \mathrm{~A}}=10 \mathrm{~mA} 	herefore$ Current through zener $=10-6.67 \mathrm{~mA}=3.37 \mathrm{~mA}$.\