The current I through 10 ohm resistor in the circuit given below is\ \

Question

Professor PC Thomas Classes · Answer

$\mathrm{D}_{2}$ does not conduct as it is reverse-biased\ \ $	herefore$ Current in $10 \Omega$ is $\frac{2 \mathrm{~V}}{25 \Omega}=80 \mathrm{~mA}$.