\ The logical operation carried out by the above circuit is\

Question

Professor PC Thomas Classes · Answer

\ The Boolean expression of the above circuit is\ $\mathrm{Y}=\overline{\overline{\mathrm{A}}} \cdot \overline{\mathrm{B}}$\ $=\overline{\overline{\mathrm{A}}} \cdot \overline{\overline{\mathrm{B}}} \quad$ (By De Morgan theorem)\ = A.B\ Hence, the logical operation carried out by the above circuit is AND gate.\