A 1000 kg car takes a round turn of radius 50 m with a velocity of $18 \mathrm{~km} / \mathrm{hr}$.

Question

A 1000 kg car takes a round turn of radius 50 m with a velocity of $18 \mathrm{~km} / \mathrm{hr}$. The centripetal force is\

Professor PC Thomas Classes · Answer

$F_{	ext {centripetal }}=\frac{m v^{2}}{R} ; \quad v=\left(18 	imes \frac{5}{18}ight) \mathrm{m} / \mathrm{s}$ $$ F_{	ext {centripetal }}=\frac{1000 	imes\left(18 	imes \frac{5}{18}ight)^{2}}{50}=500\mathrm{~N} $$