A car is moving in a circular horizontal track of radius $10\sqrt3$ m with a constant speed of $10 \

Question

A car is moving in a circular horizontal track of radius $10\sqrt3$ m with a constant speed of $10 \mathrm{~m} / \mathrm{s}$. A bob is suspended from the roof of the car by a light wire of length 1.0 m . The angle made by the wire with the vertical is\

Professor PC Thomas Classes · Answer

Let $	heta$ is the angle made by the wire with the vertical.\ $	herefore 	an 	heta=\frac{v^{2}}{r g}$\ Here, $v=10 \mathrm{~m} / \mathrm{s}, r=10\sqrt3 \mathrm{~m}, g=10 \mathrm{~m} / \mathrm{s}^{2}$\ $	herefore 	an 	heta=\frac{(10 \mathrm{~m} / \mathrm{s})^{2}}{10\sqrt3 \mathrm{~m}\left(10 \mathrm{~m} / \mathrm{s}^{2}ight)}=1/\sqrt3$ \ $ 	heta=	an ^{-1}(1/\sqrt3)=\frac{\pi}{6} $