$0.004 \mathrm{~M} \mathrm{~K}_{2} \mathrm{SO}_{4}$ solution is isotonic with 0.01 M glucose solutio

Question

$0.004 \mathrm{~M} \mathrm{~K}_{2} \mathrm{SO}_{4}$ solution is isotonic with 0.01 M glucose solution. Percentage dissociation of $\mathrm{K}_{2} \mathrm{SO}_{4}$ is --. (Nearest integer)\

Professor PC Thomas Classes · Answer

(75) : For isotonic solutions,\ $\pi_{\mathrm{K}_{2} \mathrm{SO}_{4}}=\pi_{	ext {Glucose }}$\ $i 	imes 0.004 	imes R T=0.01 	imes R T$\ $i=2.5$\ For $\mathrm{K}_{2} \mathrm{SO}_{4}$ \{for dissociation $$ i=1+(n-1) \alpha\} $$ Degree of dissociation ( $\alpha$ ) $$ =\frac{i-1}{n-1}=\frac{2.5-1}{3-1}=0.75 $$ $\%$ dissociation $=75 \%$\