An aqueous solution of $X$ is added slowly to an aqueous solution of $Y$ as shown in List I. The var

Question

An aqueous solution of $X$ is added slowly to an aqueous solution of $Y$ as shown in List I. The variation in conductivity of these reactions is given in List II. Match List I with List II and select the correct answer using the code given below the lists :

Professor PC Thomas Classes · Answer

(a) : $\mathrm{P}:\left(\mathrm{C}_{2} \mathrm{H}_{5}ight)_{3} \mathrm{~N}+\mathrm{CH}_{3} \mathrm{COOH} ightarrow$ (X)\ (Y)\ $\mathrm{CH}_{3} \mathrm{COO}_{(a q)}^{-}+\left(\mathrm{C}_{2} \mathrm{H}_{5}ight)_{3} \mathrm{NH}^{+}$ Initially conductivity increases due to ion formation after that it becomes practically constant because $X$ alone cannot form ions.\ $\mathrm{Q}: \underset{(X)}{\mathrm{KI}(0.1 \mathrm{M})}+\underset{(Y)}{\mathrm{AgNO}_{3}(0.01 \mathrm{M})} ightarrow$\ $\mathrm{AgI} \downarrow+\mathrm{KNO}_{3}$\ Number of ions in the solution remains constant until all the $\mathrm{AgNO}_{3}$ has precipitated as AgI. Thereafter conductance increases due to increase in number of ions.\ R: $\mathrm{CH}_{3} \mathrm{COOH}+\mathrm{KOH} ightarrow \mathrm{CH}_{3} \mathrm{COOK}+\mathrm{H}_{2} \mathrm{O}$\ (X) $\quad(Y)$ Initially conductance decreases due to the decrease in the number of $\mathrm{OH}^{-}$ions thereafter it slowly increases due to increase in number of $\mathrm{H}^{+}$ions.\ $\mathrm{S}: \mathrm{NaOH}+\mathrm{HI} ightarrow \mathrm{NaI}+\mathrm{H}_{2} \mathrm{O}$\ (X) $\quad(Y)$ Initially it decreases due to decrease in $\mathrm{H}^{+}$ions and then increases due to increase in $\mathrm{OH}^{-}$ions.\