A proton, a deutron and an $\alpha$-particle with the same K.E. enter a region of uniform magnetic f

Question

A proton, a deutron and an $\alpha$-particle with the same K.E. enter a region of uniform magnetic field, moving at right angles to B . What is the ratio of the radius of their circular paths\

Professor PC Thomas Classes · Answer

$\mathrm{R}=\frac{\sqrt{2 \mathrm{mE}}}{\mathrm{Bq}}$\ $\mathrm{R}_{\mathrm{p}}=\frac{\sqrt{2 	imes 1 	imes \mathrm{E}}}{\mathrm{B} 	imes \mathrm{I}}$\ $\mathrm{R}_{\mathrm{d}}=\frac{\sqrt{2 	imes 2 	imes \mathrm{E}}}{\mathrm{B} 	imes 1}$\ $\mathrm{R}_{\alpha}=\frac{\sqrt{2 	imes 4 	imes \mathrm{E}}}{\mathrm{B} 	imes 2}$\ $\mathrm{R}_{\mathrm{p}}: \mathrm{R}_{\mathrm{d}}: \mathrm{R}_{\alpha}=$\