An electron of mass $0.90 imes 10^{30} \mathrm{~kg}$ under the action of a magnetic force moves in

Question

An electron of mass $0.90 	imes 10^{30} \mathrm{~kg}$ under the action of a magnetic force moves in a circle 20 cm radius at a speed of $3.0 	imes 10^{6} \mathrm{~m} / \mathrm{sec}$. If proton of mass $1.8 	imes 10^{-27} \mathrm{~kg}$ were to move in a circle of the same radius and if it were acted upon by the same magnetic field then its speed will be\

Professor PC Thomas Classes · Answer

$\mathrm{R}_{\mathrm{e}}=\mathrm{R}_{\mathrm{p}}$\ $\frac{m_{e} v_{e}}{B q_{e}}=\frac{m_{p} v_{p}}{B q_{p}}$\ $\mathrm{q}_{\mathrm{e}}=\mathrm{q}_{\mathrm{p}}=1.6 	imes 10^{-19} \mathrm{C}$\ $	herefore \mathrm{m}_{\mathrm{e}} \mathrm{v}_{\mathrm{e}}=\mathrm{m}_{\mathrm{p}} \mathrm{v}_{\mathrm{p}}$\ $0.90 	imes 10^{-30} 	imes 3.0 	imes 10^{6}=1.8 	imes 10^{-27} 	imes \mathrm{v}_{\mathrm{p}}$\ $\mathrm{v}_{\mathrm{p}}=$\