What is the magnetic field at the point of intersections of diagonals of a current carrying square l

Question

What is the magnetic field at the point of intersections of diagonals of a current carrying square loop of each side L . The current through the loop i\

Professor PC Thomas Classes · Answer

Field due to a straight conductor of finite length is $B=\frac{\mu_{0} I}{4 \pi r}\left(\sin 	heta_{1}+\sin 	heta_{2}ight)$\ Here $	heta_{1}=45$\ $	heta_{2}=45$\ $\mathrm{r}=\frac{\mathrm{a}}{2}$\ $B$ at $o=4$ times the field due to one side\ $	herefore$ B at $0=4 	imes \frac{\mu_{0} I}{4 \pi r}[\sin 45+\sin 45]$.