The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc. $\mathrm{

Question

The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc. $\mathrm{HNO}_{3}$ to a compound with the highest oxidation state of sulphur is ______. (Given data: Molar mass of water $=18 \mathrm{~g} \mathrm{~mol}^{-1}$ )\

Professor PC Thomas Classes · Answer

(288): $: \substack{\mathrm{S}_{8} \ 1 \mathrm{~mol}} 48 \mathrm{HNO}_{3} \longrightarrow 8 \mathrm{H}_{2} \mathrm{SO}_{4}+48 \mathrm{NO}_{2}+\underset{16 \mathrm{~mol}}{16 \mathrm{H}_{2} \mathrm{O}}$\ $\Rightarrow \quad$ Mass of $\mathrm{H}_{2} \mathrm{O}$ formed $=(16 	imes 18) \mathrm{g}=288 \mathrm{~g}$\