The reaction of Xe and $\mathrm{O}_{2} \mathrm{~F}_{2}$ gives a Xe compound $P$. The number of moles

Question

The reaction of Xe and $\mathrm{O}_{2} \mathrm{~F}_{2}$ gives a Xe compound $P$. The number of moles of HF produced by the complete hydrolysis of 1 mol of $P$ is ______.\

Professor PC Thomas Classes · Answer

(4): $\mathrm{Xe}+2 \mathrm{O}_{2} \mathrm{~F}_{2} \longrightarrow \underset{(P)}{\mathrm{XeF}_{4}}+2 \mathrm{O}_{2}$\ $\underset{(P)}{3 \mathrm{XeF}_{4}}+6 \mathrm{H}_{2} \mathrm{O} \longrightarrow 2 \mathrm{Xe}+\mathrm{XeO}_{3}+\frac{3}{2} \mathrm{O}_{2}+12 \mathrm{HF}$\ The number of moles of HF given by hydrolysis of 1 mol of $\mathrm{XeF}_{4}$ is 4 .\