At 143 K , the reaction of $\mathrm{XeF}_{4}$ with $\mathrm{O}_{2} \mathrm{~F}_{2}$ produces a xenon

Question

At 143 K , the reaction of $\mathrm{XeF}_{4}$ with $\mathrm{O}_{2} \mathrm{~F}_{2}$ produces a xenon compound $Y$. The total number of lone pair(s) of electrons present on the whole molecule of $Y$ is ______ .\

Professor PC Thomas Classes · Answer

(19): $\mathrm{XeF}_{4}+\mathrm{O}_{2} \mathrm{~F}_{2} \xrightarrow{143 \mathrm{~K}} \mathrm{XeF}_{6}+\mathrm{O}_{2}$ $$  $$ In structure of $\mathrm{XeF}_{6}$, one lone pair on Xe atom, three lone pairs on each $F$ atom are present. Thus, total 19 lone pairs of electrons are present on molecule $Y$.\