MKS unit of gravitational constant is\

Question

Professor PC Thomas Classes · Answer

$\mathrm{G}=\frac{\mathrm{Fd}^{2}}{\mathrm{~m}_{1} \mathrm{~m}_{2}}=\frac{\mathrm{MLT}^{2} \mathrm{~L}^{2}}{\mathrm{MM}}=\mathrm{M}^{-1} \mathrm{~L}^{3} \mathrm{~T}^{-2}$\ $\mathrm{G}=\frac{\mathrm{Fd}^{2}}{\mathrm{~m}_{1} \mathrm{~m}_{2}}=\frac{\mathrm{Nm}^{2}}{\mathrm{~kg}^{2}}=\mathrm{kg} \frac{\mathrm{m}}{\mathrm{s}^{2}} \frac{\mathrm{~m}^{2}}{\mathrm{~kg}^{2}}$ $$ =\mathrm{kg}^{-1} \mathrm{~m}^{3} \mathrm{~s}^{-2} $$