The radius of the earth is $6.4 imes 10^{6} \mathrm{~m}$.. The acceleration due to gravity at its

Question

The radius of the earth is $6.4 	imes 10^{6} \mathrm{~m}$.. The acceleration due to gravity at its surface is $9.8 \mathrm{~m} / \mathrm{sec}^{2}$. The universal gas constant is $8.4 \mathrm{J} /$ mole K . The temperature at which oxygen molecules can escape from the surface of earth is\

Professor PC Thomas Classes · Answer

$\mathrm{v}_{\mathrm{e}}=\sqrt{2 \mathrm{rg}}$\ $\mathrm{v}_{\mathrm{ms}}=\sqrt{\frac{3 \mathrm{RT}}{\mathrm{M}}=\sqrt{2 \mathrm{rg}}} \frac{3 \mathrm{RT}}{\mathrm{M}}=2 \mathrm{rg}$\ $\mathrm{T}=\frac{\mathrm{M} 2 \mathrm{rg}}{3 \mathrm{R}}=\frac{32 	imes 2 	imes 6.4 	imes 10^{6} 	imes 9.8}{1000 	imes 3 	imes 8.4}$\ Note :- 32 g to be expressed as kg . The factor 1000 is for that purpose\