A satellite of mass $m$ is revolving round the earth at a height $R$ above the surface of the earth.

Question

A satellite of mass $m$ is revolving round the earth at a height $R$ above the surface of the earth. If $g$ is the gravitational field intensity at the earth's surface and $R$ is the radius of the earth the kinetic energy of the satellite will be\

Professor PC Thomas Classes · Answer

$\mathrm{v}_{0}=\sqrt{\mathrm{Rg}}$ \ $ \mathrm{KE}=\frac{1}{2} \mathrm{mv}_{0}^{2}=\frac{1}{2} \mathrm{mRg} $