A block of copper is heated from $20^{0} \mathrm{C}$ to $30^{0} \mathrm{C}$. Its coefficient of line

Question

A block of copper is heated from $20^{0} \mathrm{C}$ to $30^{0} \mathrm{C}$. Its coefficient of linear expansion is $1.4 	imes 10^{-5}$ degree $\mathrm{C}^{0}$ and its bulk modulus is $12 	imes 10^{11}$ dyne $/ \mathrm{cm}^{2}$. The hydrostatic pressure needed to stop expansion is\

Professor PC Thomas Classes · Answer

$\mathrm{K}=\frac{\mathrm{PV}}{\mathrm{dv}}$ numerically 
$ P=\frac{K d v}{V} $
 But dv $=\mathrm{V}\left(\alpha_{\mathrm{v}}ight) \Delta 	heta$ 
$ \begin{aligned} & =\mathrm{V}\left(3 \alpha_{1}ight) \Delta 	heta \ & 	herefore \mathrm{P}=\frac{\mathrm{KV}\left(3 \alpha_{1}ight) \Delta 	heta}{\mathrm{V}} \ & =\mathrm{K} 3 \alpha_{1} \Delta 	heta \ & \mathrm{~K}=12 	imes 10^{11} \mathrm{dyne} / \mathrm{cm}^{2} \ & \alpha_{1}=1.4 	imes 10^{-5} /{ }^{0} \mathrm{C} \ & \Delta 	heta=30-20=10^{0} \mathrm{C} \end{aligned} $
 Substitute & get P .\