Acceleration due to gravity at a place is ` $g$ '. If a sphere of density $d$ is placed on the surfa

Question

Acceleration due to gravity at a place is ` $g$ '. If a sphere of density $d$ is placed on the surface of non viscous liquid of density\ $\mathrm{D}(\mathrm{d}>\mathrm{D})$. The acceleration of the sphere will be\

Professor PC Thomas Classes · Answer

$\mathrm{g}^{1}=\mathrm{g}\left[1-\frac{\mathrm{d}_{\ell}}{\mathrm{d}_{\mathrm{s}}}ight]$\ where $\mathrm{g}=$ acceleration due to gravity in air or vacuum\ $\mathrm{g}^{1}=$ effective acceleration due to gravity in the liquid\ $\mathrm{d}_{\mathrm{s}}=$ density of solid; $\mathrm{d}_{l}=$ density of liquid Here $\mathrm{d}_{\mathrm{s}}=\mathrm{d}, \mathrm{d}_{1}=\mathrm{D}$\ Calculate $\mathrm{g}^{1}$