An electron accelerated under a potential difference of $V$ volts has a certain wavelength $\lambda$

Question

An electron accelerated under a potential difference of $V$ volts has a certain wavelength $\lambda$. Mass of the proton is $\approx 2000$ times the mass of an electron. If the proton has to have the same wavelength $\lambda$., then it will have to be accelerated under a potential difference of\

Professor PC Thomas Classes · Answer

$\lambda=\frac{\mathrm{h}}{\sqrt{2 \mathrm{mVq}}}$ $$ \lambda_{\mathrm{e}}=\lambda_{\mathrm{p}} $$ $\frac{\mathrm{h}}{\sqrt{2 	imes 1 	imes \mathrm{V} 	imes 1}}=\frac{\mathrm{h}}{\sqrt{2 	imes 2000 	imes \mathrm{V}^{1} 	imes 1}}$\ $	herefore V^{1}=$\