When radiation is incident on a photoelectron emitter, the stopping potential is found to 9 volts. I

Question

When radiation is incident on a photoelectron emitter, the stopping potential is found to 9 volts. If $\mathrm{e} / \mathrm{m}$ for the electron is $1.8 	imes 10^{11} \mathrm{C} \mathrm{kg}^{-1}$ the maximum velocity of the ejected electrons is\

Professor PC Thomas Classes · Answer

Maximum velocity of the ejected electron is \end{enumerate} $$ \mathrm{eV}=\frac{1}{2} \mathrm{mv}_{\max }^{2} $$ Where V is the potential difference, $\mathrm{v}_{	ext {max }}$ is the maximum speed $$ \begin{aligned} \frac{2 \mathrm{eV}}{\mathrm{~m}} & =\mathrm{v}_{\max }^{2}=2 	imes 1.8 	imes 10^{11} 	imes 9 \ \mathrm{v}_{\max } & =18 	imes 10^{5} \mathrm{~m} / \mathrm{s}=1.8 	imes 10^{6} \mathrm{~m} / \mathrm{s} \end{aligned} $$