The maximum kinetic energy of photoelectrons\

Question

Professor PC Thomas Classes · Answer

The maximum kinetic energy of photoelectrons $$ \mathrm{K}_{\max }=\mathrm{h} v-\phi-\mathrm{h} v-\mathrm{hv}_{0} $$ Here, $v_{0}$ is different for different emitting surfaces. Therefore, the maximum kinetic energy of electrons emitted depends on the frequency of the incident light and the nature of emitter plate material It does not depend on the intensity of incident light.\