If alpha particle, proton and electron move with the same momentum, then their respective de Broglie

Question

If alpha particle, proton and electron move with the same momentum, then their respective de Broglie wavelengths $\lambda_{a}, \lambda_{p}, \lambda_{e}$ are related as\

Professor PC Thomas Classes · Answer

de Broglie wavelength, $\lambda=\frac{\mathrm{h}}{\mathrm{p}}$ Where symbol have their usual meanings.\ $\because \mathrm{p}_{\mathrm{a}}=\mathrm{p}_{\mathrm{p}}=\mathrm{p}_{\mathrm{e}} 	herefore \lambda_{\mathrm{e}}=\lambda_{\mathrm{p}}=\lambda_{\mathrm{c}}$\