For the equilibrium\ $\mathrm{PCl}_{5(\mathrm{~g})} ightleftharpoons \mathrm{PCl}_{3(\mathrm{~g})

Question

For the equilibrium\ $\mathrm{PCl}_{5(\mathrm{~g})} ightleftharpoons \mathrm{PCl}_{3(\mathrm{~g})}+\mathrm{Cl}_{2(\mathrm{~g})}, \mathrm{K}_{\mathrm{p}} / \mathrm{K}_{\mathrm{c}}$ is found to be equal to $24.63 \mathrm{~atm} \mathrm{~L} \mathrm{~mol}^{-1}$ at a certain temperature, T . Then T is equal to\

Professor PC Thomas Classes · Answer

$\frac{\mathrm{K}_{\mathrm{p}}}{\mathrm{K}_{\mathrm{C}}}=(\mathrm{RT})^{\Delta \mathrm{n}}$. Hence $24.63=[(.0821) 	imes(\mathrm{T})]^{1}$\ $\mathrm{T}=\frac{24.63}{0821}=300 \mathrm{~K}$\