For the reaction $\mathrm{N}_{2} \mathrm{O}_{4} \rightleftharpoons 2 \mathrm{NO}_{2}, \mathrm{Kp}$ i

Question

For the reaction $\mathrm{N}_{2} \mathrm{O}_{4} ightleftharpoons 2 \mathrm{NO}_{2}, \mathrm{Kp}$ is given by\

Professor PC Thomas Classes · Answer

$\mathrm{N}_{2} \mathrm{O}_{4} ightarrow 2 \mathrm{NO}$\ $1-\alpha \quad 2 \alpha \quad$ Total $1+\propto$\ $\mathrm{K}_{\mathrm{p}} \frac{\left[\frac{2 \alpha}{1+\alpha} \mathrm{P}ight]^{2}}{\left(\frac{1-\alpha}{1+\alpha} \mathrm{P}ight)}=\frac{4 \alpha^{2} \mathrm{P}}{1-\alpha^{2}}$\