A microscope was initially placed in air (refractive index 1). It is then immersed in oil (refractiv

Question

A microscope was initially placed in air (refractive index 1). It is then immersed in oil (refractive index 2). For a light whose wavelength in air is $\lambda$, calculate the change of microscope's resolving power due to oil and choose the correct option.\

Professor PC Thomas Classes · Answer

(b) : Resolving power of a microscope, $(	ext { R.P })_{	ext {air }}=\frac{2 \sin 	heta}{1.22 \lambda} ; \quad(	ext { R.P })_{	ext {oil }}=\frac{2 \sin 	heta 	imes \mu}{1.22 \lambda}$\ $(	ext { R.P })_{	ext {oil }}=(	ext { R.P })_{	ext {air }} 	imes 2$\