The least count of a screw gauge is 0.01 mm . If the pitch is increased by $75 \%$ and number of div

Question

The least count of a screw gauge is 0.01 mm . If the pitch is increased by $75 \%$ and number of divisions on the circular scale is reduced by $50 \%$, the new least count will be $\_\_\_\_$ $	imes 10^{-3} \mathrm{~mm}$.\

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