In the reaction of $\mathrm{KMnO}_{4}$ with an oxalate in acidic medium, $\mathrm{MnO}_{4}^{-}$is re

Question

In the reaction of $\mathrm{KMnO}_{4}$ with an oxalate in acidic medium, $\mathrm{MnO}_{4}^{-}$is reduced to $\mathrm{Mn}^{2+}$ and $\mathrm{C}_{2} \mathrm{O}_{4}^{2-}$ is oxidised to $\mathrm{CO}_{2}$. Hence, 50 mL of $0.02 \mathrm{~M} \mathrm{~KMnO}_{4}$ is equivalent to\

Professor PC Thomas Classes · Answer

(b) : Equivalent mass of $\mathrm{MnO}_{4}^{-}=\frac{	ext { Molar mass }}{5}$ \Equivalent mass of $\mathrm{C}_{2} \mathrm{O}_{4}^{2-}=\frac{	ext { Molar mass }}{2}$\ Milliequivalent of $\mathrm{KMnO}_{4}=50 	imes 5 	imes 0.02=5$\ Milliequivalent of $\mathrm{C}_{2} \mathrm{O}_{4}{ }^{2-}=50 	imes 0.05 	imes 2=5$\