A student performs a titration with different burettes and finds titre values of $25.2 \mathrm{~mL},

Question

A student performs a titration with different burettes and finds titre values of $25.2 \mathrm{~mL}, 25.25 \mathrm{~mL}$, and $25.0 \mathrm{~mL}$ . The number of significant figures in the average titre value is\

Professor PC Thomas Classes · Answer

(a) : Average titre value $=\frac{25.2+25.25+25.0}{3}=25.15$ \According to rounding off rule of significant figures, if the right most digit to be removed is 5 , then the preceding number is not changed, if it is even; but increased by one, if it is odd.\ $	herefore \quad 25.15$ can be rounded off to 25.2 and has three significant figures.\