For every one ${ }^{37} \mathrm{Cl}$ isotope there are three ${ }^{35} \mathrm{Cl}$ isotopes in a sa

Question

For every one ${ }^{37} \mathrm{Cl}$ isotope there are three ${ }^{35} \mathrm{Cl}$ isotopes in a sample of chlorine. What will be the average atomic mass of chlorine?\

Professor PC Thomas Classes · Answer

(c) : Average atomic mass of chlorine $$ =\frac{3 	imes 35+37 	imes 1}{4}=35.5 $$