The empirical formula of a compound is $\mathrm{CH}_{2} \mathrm{O}_{2}$. What could be its molecular

Question

The empirical formula of a compound is $\mathrm{CH}_{2} \mathrm{O}_{2}$. What could be its molecular formula?\

Professor PC Thomas Classes · Answer

(c) : Since, empirical formula is multiplied by $n$ to get molecular formula, $\left(\mathrm{CH}_{2} \mathrm{O}_{2}ight)_{n}$ where $n=1,2,3, \ldots$ etc. Hence, among the given options $\mathrm{CH}_{2} \mathrm{O}_{2}$ will give only $\mathrm{C}_{2} \mathrm{H}_{4} \mathrm{O}_{4}$ as its molecular formula.\