If 1.5 moles of oxygen combine with Al to form $\mathrm{Al}_{2} \mathrm{O}_{3}$, the mass of Al in g

Question

If 1.5 moles of oxygen combine with Al to form $\mathrm{Al}_{2} \mathrm{O}_{3}$, the mass of Al in g [atomic mass of $\mathrm{Al}=27$ ] used in the reaction is\

Professor PC Thomas Classes · Answer

(b) : The equation for the formation of $\mathrm{Al}_{2} \mathrm{O}_{3}$ is\ Thus, 1 mole of alumina is obtained by the reaction of 1.5 moles of oxygen and 2 moles of aluminium. Thus, the amount of aluminium $=2$ moles $$ =2 	imes 27 \mathrm{~g}=54 \mathrm{~g} $$