An organic compound $P$ with molecular formula $\mathrm{C}_{9} \mathrm{H}_{18} \mathrm{O}_{2}$ decol

Question

An organic compound $P$ with molecular formula $\mathrm{C}_{9} \mathrm{H}_{18} \mathrm{O}_{2}$ decolorizes bromine water and also shows positive iodoform test. $P$ on ozonolysis followed by treatment with $\mathrm{H}_{2} \mathrm{O}_{2}$ gives $Q$ and $R$. While compound $Q$ shows positive iodoform test, compound $R$ does not give positive iodoform test. $Q$ and $R$ on oxidation with pyridinium chlorochromate (PCC) followed by heating give $S$ and $T$, respectively. Both $S$ and $T$ show positive iodoform test.\ Complete copolymerization of 500 moles of $Q$ and 500 moles of $R$ gives one mole of a single acyclic copolymer $U$.\ [Given, atomic mass: $\mathrm{H}=1, \mathrm{C}=12, \mathrm{O}=16$ ]\The molecular weight of $U$ is $\_\_\_\_$ .\

Professor PC Thomas Classes · Answer

(93018) :
 Molecular mass of 3-hydroxy pentanoic acid = 118\ Molecular mass of 3-hydroxy butanoic acid = 104\ Loss due to removal of water $=18 	imes 999$\ Molecular weight of polymer\ $=104 	imes 500+118 	imes 500-(18 	imes 999)$\ $=52000+59,000-17982=93018$\