$X \mathrm{~g}$ of nitrobenzene on nitration gave 4.2 g of $m$-dinitrobenzene. $X=$ $\_\_\_\_$ g. (n

Question

$X \mathrm{~g}$ of nitrobenzene on nitration gave 4.2 g of $m$-dinitrobenzene. $X=$ $\_\_\_\_$ g. (nearest integer}\ [Given: molar mass (in $\mathrm{g} \mathrm{mol}^{-1}$ ) $\mathrm{C}: 12, \mathrm{H}: 1, \mathrm{O}: 16$, N: 14]\

Professor PC Thomas Classes · Answer

(3)  No. of moles of product $=\frac{4.2}{168}=0.025 \mathrm{~mol}$\ $	herefore \quad$ Mass of nitrobenzene $(X)=(0.025 	imes 123) \mathrm{g}=3.075 \mathrm{~g}$\