Among $10^{-9} \mathrm{~g}$ (each) of the following elements, which one will have the highest number

Question

Among $10^{-9} \mathrm{~g}$ (each) of the following elements, which one will have the highest number of atoms?\ Element: $\mathrm{Pb}, \mathrm{Po}, \mathrm{Pr}$ and Pt\

Professor PC Thomas Classes · Answer

(a): Higher the number of moles of an element, higher will be the number of atoms. $$ 	ext { Number of moles }=\frac{	ext { Mass }}{	ext { Atomic mass }} $$ Atomic mass of $\mathrm{Pr}=141, \mathrm{~Pb}=207$, $\mathrm{Pt}=195, \mathrm{Po}=209$.\ The highest number of atoms will be of Pr as its atomic mass is least among all.\