Quantitative analysis of an organic compound ( $X$ ) shows following \% composition.\ C : 14.5%\ C

Question

Quantitative analysis of an organic compound ( $X$ ) shows following \% composition.\ C : 14.5%\ Cl : 64.46%\ H : 1.8%\ Empirical formula mass of the compound $(X)$ is $\_\_\_\_$ $	imes 10^{-1}$.\ (Given molar mass in $\mathrm{g} \mathrm{mol}^{-1}$ of $\mathrm{C}: 12, \mathrm{H}: 1, \mathrm{O}: 16$,\ Cl: 35.5 )\

Professor PC Thomas Classes · Answer

(1655) :  Empirical formula $=\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2} \mathrm{Cl}_{3}$\ Empirical formula mass\ $=2 	imes 12+3 	imes 1+2 	imes 16+35.5 	imes 3$\ $=24+3+32+106.5=165.5$\ Hence, empirical formula mass of the compound $(X)$ is $1655 	imes 10^{-1}$.\