For hydrogen atom, the orbital/s with lowest energy is/are :\ (A) $4 s$\ (B) $3 p_{x}$\ (C) $3 d_

Question

For hydrogen atom, the orbital/s with lowest energy is/are :\ (A) $4 s$\ (B) $3 p_{x}$\ (C) $3 d_{x^{2}-y^{2}}$\ (D) $3 d_{z^{2}}$\ (E) $4 p_{z}$ \Choose the correct answer from the options given below :\

Professor PC Thomas Classes · Answer

(d): For hydrogen atom, energy of orbitals is in the order $1 s<2 s=2 p <3 s=3 p=3 d<4 s=4 p=4 d=4 f$\ Thus B, C, and D have same energy, which is lower than energy of $A$ and $E$.\