Given $ riangle A B C \sim riangle P Q R, \angle A=30^{\circ}$ and $\angle Q=90^{\circ}$. The val

Question

Given $	riangle A B C \sim 	riangle P Q R, \angle A=30^{\circ}$ and $\angle Q=90^{\circ}$. The value of $(\angle R+\angle B)$ is\

Professor PC Thomas Classes · Answer

(c): Given, $	riangle A B C \sim 	riangle P Q R, \angle A=30^{\circ}, \angle Q=90^{\circ}$ Since, $	riangle A B C \sim 	riangle P Q R$\ $\angle A=\angle P=30^{\circ}, \angle B=\angle Q=90^{\circ}$\ So, $\angle C=\angle R=180^{\circ}-90^{\circ}-30^{\circ}=60^{\circ}$\ $\Rightarrow \quad(\angle R+\angle B)=\left(60^{\circ}+90^{\circ}ight)=150^{\circ}$\