In the given figure, in $ riangle A B C, D E \| B C$. If $A D=2.4 \mathrm{~cm}$, $D B=4 \mathrm{~cm

Question

In the given figure, in $	riangle A B C, D E \| B C$. If $A D=2.4 \mathrm{~cm}$, $D B=4 \mathrm{~cm}$ and $A E=2 \mathrm{~cm}$, then the length of $A C$ is\

Professor PC Thomas Classes · Answer

(c): In $	riangle A B C, D E \| B C$ By Basic Proportionality Theorem,\ $\frac{A D}{D B}=\frac{A E}{E C}$\ $\Rightarrow \frac{2.4}{4}=\frac{2}{E C} \Rightarrow E C=\frac{2 	imes 4 	imes 10}{24}$\ $\Rightarrow E C=\frac{10}{3}$\ $	herefore \quad A C=A E+E C=2+\frac{10}{3}=\frac{16}{3} \mathrm{~cm}$\