In the given figure, $x$ expressed in terms of $a, b, c$, is

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Professor PC Thomas Classes · Answer

(b): In $	riangle R S T$ and $	riangle R P Q$,\ $\angle R=\angle R$ [Common]\ $\angle R T S=\angle R Q P=47^{\circ}$ [Given]\ $	herefore \quad 	riangle R S T \sim 	riangle R P Q$ [By AA similarity]\ $	herefore \quad \frac{S T}{P Q}=\frac{R T}{R Q} \Rightarrow \frac{x}{a}=\frac{c}{c+b} \Rightarrow x=\frac{a c}{b+c}$