Given HCF $(2520,6600)=40, \operatorname{LCM}(2520,6600) =252 imes k$, then the value of $k$ is :\

Question

Given HCF $(2520,6600)=40, \operatorname{LCM}(2520,6600) =252 	imes k$, then the value of $k$ is :\

Professor PC Thomas Classes · Answer

(a): $\operatorname{HCF}(2550,6600)=40$ Now, $\operatorname{LCM}(2520,6600)=252 	imes k$\ HCF × LCM = Product of numbers\ $	herefore \quad 40 	imes 252 	imes k=2520 	imes 6600=16632000=40 	imes 252 	imes k$\ $\Rightarrow \mathrm{k}=1650$ \ Concept Applied - Product of two numbers is equal to the product of their HCF and LCM. Note: There is an error in question as HCF $(2520,6600) =120$.\