Zeroes of the polynomial $p(y)=7 y^{2}-\frac{11}{3} y-\frac{2}{3}$ are:\

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(d) : The given polynomial is $p(y)=7 y^{2}-\frac{11 y}{3}-\frac{2}{3}$\ $\Rightarrow \quad p(y)=\frac{21 y^{2}-11 y-2}{3}=\frac{(7 y+1)(3 y-2)}{3}$\ For zeroes of the polynomial, put $p(y)=0$\ $\Rightarrow \quad \frac{(7 y+1)(3 y-2)}{3}=0 \Rightarrow y=\frac{-1}{7}, \frac{2}{3}$