The zeroes of the quadratic polynomial $2 x^{2}-3 x-9$ are:\

Question

Professor PC Thomas Classes · Answer

(a): We have, $p(x)=2 x^{2}-3 x-9$\ $\Rightarrow p(x)=2 x^{2}-6 x+3 x-9$ $$ =2 x(x-3)+3(x-3)=(x-3)(2 x+3) $$ For zeros of the polynomial $p(x)$,\ Put $p(x)=0$\ $\Rightarrow \quad(x-3)(2 x+3)=0$\ $\Rightarrow \quad(x-3)=0$ or $(2 x+3)=0 \Rightarrow x=3,-3 / 2$\