The zeroes of the polynomial $3 x^{2}+11 x-4$ are :\

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Professor PC Thomas Classes · Answer

(c) : The given polynomial is $3 x^{2}+11 x-4$ $$ =3 x^{2}+12 x-x-4=3 x(x+4)-1(x+4)=(3 x-1)(x+4) $$ So, the value of $3 x^{2}+11 x-4$ is zero when $$ x=1 / 3 	ext { or } x=-4 $$ $	herefore \quad 1 / 3$ and -4 are zeroes of the given polynomial.\