If one of the zeroes of a quadratic polynomial $(k-1) x^{2}+k x+1$ is -3 , then the value of $k$ is\

Question

Professor PC Thomas Classes · Answer

(a) : Given, -3 is a zero of quadratic polynomial 
$ (k-1) x^{2}+k x+1 . $
 $	herefore \quad(k-1)(-3)^{2}+k(-3)+1=0$\ $\Rightarrow 9 k-9-3 k+1=0 \Longrightarrow 6 k-8=0 \Rightarrow k=8 / 6 \Rightarrow k=\frac{4}{3}$\