If the sum of zeroes of the polynomial $p(x)=2 x^{2}-k \sqrt{2} x+1$ is $\sqrt{2}$, then value of $k

Question

If the sum of zeroes of the polynomial $p(x)=2 x^{2}-k \sqrt{2} x+1$ is $\sqrt{2}$, then value of $k$ is :\

Professor PC Thomas Classes · Answer

(b) : Given, sum of zeroes of the given polynomial is $\sqrt{2}$\ $\Rightarrow-\frac{(-k \sqrt{2})}{2}=\sqrt{2} \Rightarrow k=\frac{2 \sqrt{2}}{\sqrt{2}}=2$