The value of $k$ for which the system of equations $x+y-4=0$ and $2 x+k y=3$, has no solution, is\

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(d) : ∵ The given system of equations will have no solution.\ $	herefore \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}} 
eq \frac{c_{1}}{c_{2}} \Rightarrow \frac{1}{2}=\frac{1}{k} 
eq \frac{-4}{-3}$\ $\Rightarrow \frac{1}{2}=\frac{1}{k} \Rightarrow k=2$\ Clearly, $\frac{1}{k} 
eq \frac{-4}{-3}$ for $k=2$\ Hence, the given system of equations will have no solution for $k=2$.\